4(b-3)=2(2b+1)

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Solution for 4(b-3)=2(2b+1) equation:


Simplifying
4(b + -3) = 2(2b + 1)

Reorder the terms:
4(-3 + b) = 2(2b + 1)
(-3 * 4 + b * 4) = 2(2b + 1)
(-12 + 4b) = 2(2b + 1)

Reorder the terms:
-12 + 4b = 2(1 + 2b)
-12 + 4b = (1 * 2 + 2b * 2)
-12 + 4b = (2 + 4b)

Add '-4b' to each side of the equation.
-12 + 4b + -4b = 2 + 4b + -4b

Combine like terms: 4b + -4b = 0
-12 + 0 = 2 + 4b + -4b
-12 = 2 + 4b + -4b

Combine like terms: 4b + -4b = 0
-12 = 2 + 0
-12 = 2

Solving
-12 = 2

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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