4(b-3)+2(b+2)=2(b-2)

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Solution for 4(b-3)+2(b+2)=2(b-2) equation:


Simplifying
4(b + -3) + 2(b + 2) = 2(b + -2)

Reorder the terms:
4(-3 + b) + 2(b + 2) = 2(b + -2)
(-3 * 4 + b * 4) + 2(b + 2) = 2(b + -2)
(-12 + 4b) + 2(b + 2) = 2(b + -2)

Reorder the terms:
-12 + 4b + 2(2 + b) = 2(b + -2)
-12 + 4b + (2 * 2 + b * 2) = 2(b + -2)
-12 + 4b + (4 + 2b) = 2(b + -2)

Reorder the terms:
-12 + 4 + 4b + 2b = 2(b + -2)

Combine like terms: -12 + 4 = -8
-8 + 4b + 2b = 2(b + -2)

Combine like terms: 4b + 2b = 6b
-8 + 6b = 2(b + -2)

Reorder the terms:
-8 + 6b = 2(-2 + b)
-8 + 6b = (-2 * 2 + b * 2)
-8 + 6b = (-4 + 2b)

Solving
-8 + 6b = -4 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
-8 + 6b + -2b = -4 + 2b + -2b

Combine like terms: 6b + -2b = 4b
-8 + 4b = -4 + 2b + -2b

Combine like terms: 2b + -2b = 0
-8 + 4b = -4 + 0
-8 + 4b = -4

Add '8' to each side of the equation.
-8 + 8 + 4b = -4 + 8

Combine like terms: -8 + 8 = 0
0 + 4b = -4 + 8
4b = -4 + 8

Combine like terms: -4 + 8 = 4
4b = 4

Divide each side by '4'.
b = 1

Simplifying
b = 1

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