4(b-2)=6b-7

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Solution for 4(b-2)=6b-7 equation:



4(b-2)=6b-7
We move all terms to the left:
4(b-2)-(6b-7)=0
We multiply parentheses
4b-(6b-7)-8=0
We get rid of parentheses
4b-6b+7-8=0
We add all the numbers together, and all the variables
-2b-1=0
We move all terms containing b to the left, all other terms to the right
-2b=1
b=1/-2
b=-1/2

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