4(b-2)-20=2(b+3)

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Solution for 4(b-2)-20=2(b+3) equation:


Simplifying
4(b + -2) + -20 = 2(b + 3)

Reorder the terms:
4(-2 + b) + -20 = 2(b + 3)
(-2 * 4 + b * 4) + -20 = 2(b + 3)
(-8 + 4b) + -20 = 2(b + 3)

Reorder the terms:
-8 + -20 + 4b = 2(b + 3)

Combine like terms: -8 + -20 = -28
-28 + 4b = 2(b + 3)

Reorder the terms:
-28 + 4b = 2(3 + b)
-28 + 4b = (3 * 2 + b * 2)
-28 + 4b = (6 + 2b)

Solving
-28 + 4b = 6 + 2b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-2b' to each side of the equation.
-28 + 4b + -2b = 6 + 2b + -2b

Combine like terms: 4b + -2b = 2b
-28 + 2b = 6 + 2b + -2b

Combine like terms: 2b + -2b = 0
-28 + 2b = 6 + 0
-28 + 2b = 6

Add '28' to each side of the equation.
-28 + 28 + 2b = 6 + 28

Combine like terms: -28 + 28 = 0
0 + 2b = 6 + 28
2b = 6 + 28

Combine like terms: 6 + 28 = 34
2b = 34

Divide each side by '2'.
b = 17

Simplifying
b = 17

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