4(b-1)=2(5-b)

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Solution for 4(b-1)=2(5-b) equation: 



4(b-1)=2(5-b)

We move all terms to the left:

4(b-1)-(2(5-b))=0

We add all the numbers together, and all the variables

4(b-1)-(2(-1b+5))=0

We multiply parentheses

4b-(2(-1b+5))-4=0



We calculate terms in parentheses: -(2(-1b+5)), so:

2(-1b+5)

We multiply parentheses

-2b+10

Back to the equation:

-(-2b+10)



We get rid of parentheses

4b+2b-10-4=0

We add all the numbers together, and all the variables

6b-14=0

We move all terms containing b to the left, all other terms to the right

6b=14

b=14/6

b=2+1/3

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