4(b+5)-10=2(-b-7)-6b

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Solution for 4(b+5)-10=2(-b-7)-6b equation:



4(b+5)-10=2(-b-7)-6b
We move all terms to the left:
4(b+5)-10-(2(-b-7)-6b)=0
We add all the numbers together, and all the variables
4(b+5)-(2(-1b-7)-6b)-10=0
We multiply parentheses
4b-(2(-1b-7)-6b)+20-10=0
We calculate terms in parentheses: -(2(-1b-7)-6b), so:
2(-1b-7)-6b
We add all the numbers together, and all the variables
-6b+2(-1b-7)
We multiply parentheses
-6b-2b-14
We add all the numbers together, and all the variables
-8b-14
Back to the equation:
-(-8b-14)
We add all the numbers together, and all the variables
4b-(-8b-14)+10=0
We get rid of parentheses
4b+8b+14+10=0
We add all the numbers together, and all the variables
12b+24=0
We move all terms containing b to the left, all other terms to the right
12b=-24
b=-24/12
b=-2

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