4(b+5)+6=2(2b-3)

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Solution for 4(b+5)+6=2(2b-3) equation:



4(b+5)+6=2(2b-3)
We move all terms to the left:
4(b+5)+6-(2(2b-3))=0
We multiply parentheses
4b-(2(2b-3))+20+6=0
We calculate terms in parentheses: -(2(2b-3)), so:
2(2b-3)
We multiply parentheses
4b-6
Back to the equation:
-(4b-6)
We add all the numbers together, and all the variables
4b-(4b-6)+26=0
We get rid of parentheses
4b-4b+6+26=0
We add all the numbers together, and all the variables
32!=0
There is no solution for this equation

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