4(b+3)=3b+30

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Solution for 4(b+3)=3b+30 equation: 



4(b+3)=3b+30

We move all terms to the left:

4(b+3)-(3b+30)=0

We multiply parentheses

4b-(3b+30)+12=0

We get rid of parentheses

4b-3b-30+12=0

We add all the numbers together, and all the variables

b-18=0

We move all terms containing b to the left, all other terms to the right

b=18

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