4(b+3)=2(b+12)

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Solution for 4(b+3)=2(b+12) equation: 



4(b+3)=2(b+12)

We move all terms to the left:

4(b+3)-(2(b+12))=0

We multiply parentheses

4b-(2(b+12))+12=0



We calculate terms in parentheses: -(2(b+12)), so:

2(b+12)

We multiply parentheses

2b+24

Back to the equation:

-(2b+24)



We get rid of parentheses

4b-2b-24+12=0

We add all the numbers together, and all the variables

2b-12=0

We move all terms containing b to the left, all other terms to the right

2b=12

b=12/2

b=6

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