4(b+3)-7(b-6)=75

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Solution for 4(b+3)-7(b-6)=75 equation: 



4(b+3)-7(b-6)=75

We move all terms to the left:

4(b+3)-7(b-6)-(75)=0

We multiply parentheses

4b-7b+12+42-75=0

We add all the numbers together, and all the variables

-3b-21=0

We move all terms containing b to the left, all other terms to the right

-3b=21

b=21/-3

b=-7

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