4(b+3)+b=4(b-2)-1

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Solution for 4(b+3)+b=4(b-2)-1 equation:


Simplifying
4(b + 3) + b = 4(b + -2) + -1

Reorder the terms:
4(3 + b) + b = 4(b + -2) + -1
(3 * 4 + b * 4) + b = 4(b + -2) + -1
(12 + 4b) + b = 4(b + -2) + -1

Combine like terms: 4b + b = 5b
12 + 5b = 4(b + -2) + -1

Reorder the terms:
12 + 5b = 4(-2 + b) + -1
12 + 5b = (-2 * 4 + b * 4) + -1
12 + 5b = (-8 + 4b) + -1

Reorder the terms:
12 + 5b = -8 + -1 + 4b

Combine like terms: -8 + -1 = -9
12 + 5b = -9 + 4b

Solving
12 + 5b = -9 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
12 + 5b + -4b = -9 + 4b + -4b

Combine like terms: 5b + -4b = 1b
12 + 1b = -9 + 4b + -4b

Combine like terms: 4b + -4b = 0
12 + 1b = -9 + 0
12 + 1b = -9

Add '-12' to each side of the equation.
12 + -12 + 1b = -9 + -12

Combine like terms: 12 + -12 = 0
0 + 1b = -9 + -12
1b = -9 + -12

Combine like terms: -9 + -12 = -21
1b = -21

Divide each side by '1'.
b = -21

Simplifying
b = -21

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