4(b+1)=-b+6(b-2)

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Solution for 4(b+1)=-b+6(b-2) equation:


Simplifying
4(b + 1) = -1b + 6(b + -2)

Reorder the terms:
4(1 + b) = -1b + 6(b + -2)
(1 * 4 + b * 4) = -1b + 6(b + -2)
(4 + 4b) = -1b + 6(b + -2)

Reorder the terms:
4 + 4b = -1b + 6(-2 + b)
4 + 4b = -1b + (-2 * 6 + b * 6)
4 + 4b = -1b + (-12 + 6b)

Reorder the terms:
4 + 4b = -12 + -1b + 6b

Combine like terms: -1b + 6b = 5b
4 + 4b = -12 + 5b

Solving
4 + 4b = -12 + 5b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-5b' to each side of the equation.
4 + 4b + -5b = -12 + 5b + -5b

Combine like terms: 4b + -5b = -1b
4 + -1b = -12 + 5b + -5b

Combine like terms: 5b + -5b = 0
4 + -1b = -12 + 0
4 + -1b = -12

Add '-4' to each side of the equation.
4 + -4 + -1b = -12 + -4

Combine like terms: 4 + -4 = 0
0 + -1b = -12 + -4
-1b = -12 + -4

Combine like terms: -12 + -4 = -16
-1b = -16

Divide each side by '-1'.
b = 16

Simplifying
b = 16

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