4(b+1)+4b=36

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Solution for 4(b+1)+4b=36 equation:



4(b+1)+4b=36
We move all terms to the left:
4(b+1)+4b-(36)=0
We add all the numbers together, and all the variables
4b+4(b+1)-36=0
We multiply parentheses
4b+4b+4-36=0
We add all the numbers together, and all the variables
8b-32=0
We move all terms containing b to the left, all other terms to the right
8b=32
b=32/8
b=4

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