4(a-3)=8a-(54a+12)

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Solution for 4(a-3)=8a-(54a+12) equation: 



4(a-3)=8a-(54a+12)

We move all terms to the left:

4(a-3)-(8a-(54a+12))=0

We multiply parentheses

4a-(8a-(54a+12))-12=0



We calculate terms in parentheses: -(8a-(54a+12)), so:

8a-(54a+12)

We get rid of parentheses

8a-54a-12

We add all the numbers together, and all the variables

-46a-12

Back to the equation:

-(-46a-12)



We get rid of parentheses

4a+46a+12-12=0

We add all the numbers together, and all the variables

50a=0

a=0/50

a=0

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