4(a-3)+2=2(2a-5)

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Solution for 4(a-3)+2=2(2a-5) equation:


Simplifying
4(a + -3) + 2 = 2(2a + -5)

Reorder the terms:
4(-3 + a) + 2 = 2(2a + -5)
(-3 * 4 + a * 4) + 2 = 2(2a + -5)
(-12 + 4a) + 2 = 2(2a + -5)

Reorder the terms:
-12 + 2 + 4a = 2(2a + -5)

Combine like terms: -12 + 2 = -10
-10 + 4a = 2(2a + -5)

Reorder the terms:
-10 + 4a = 2(-5 + 2a)
-10 + 4a = (-5 * 2 + 2a * 2)
-10 + 4a = (-10 + 4a)

Add '10' to each side of the equation.
-10 + 10 + 4a = -10 + 10 + 4a

Combine like terms: -10 + 10 = 0
0 + 4a = -10 + 10 + 4a
4a = -10 + 10 + 4a

Combine like terms: -10 + 10 = 0
4a = 0 + 4a
4a = 4a

Add '-4a' to each side of the equation.
4a + -4a = 4a + -4a

Combine like terms: 4a + -4a = 0
0 = 4a + -4a

Combine like terms: 4a + -4a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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