4(a-2)=3(a+40)

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Solution for 4(a-2)=3(a+40) equation: 



4(a-2)=3(a+40)

We move all terms to the left:

4(a-2)-(3(a+40))=0

We multiply parentheses

4a-(3(a+40))-8=0



We calculate terms in parentheses: -(3(a+40)), so:

3(a+40)

We multiply parentheses

3a+120

Back to the equation:

-(3a+120)



We get rid of parentheses

4a-3a-120-8=0

We add all the numbers together, and all the variables

a-128=0

We move all terms containing a to the left, all other terms to the right

a=128

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