4(a-2)-(2a-5)=19

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Solution for 4(a-2)-(2a-5)=19 equation: 



4(a-2)-(2a-5)=19

We move all terms to the left:

4(a-2)-(2a-5)-(19)=0

We multiply parentheses

4a-(2a-5)-8-19=0

We get rid of parentheses

4a-2a+5-8-19=0

We add all the numbers together, and all the variables

2a-22=0

We move all terms containing a to the left, all other terms to the right

2a=22

a=22/2

a=11

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