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4(a+5)+6=2(2a+3)
We move all terms to the left:
4(a+5)+6-(2(2a+3))=0
We multiply parentheses
4a-(2(2a+3))+20+6=0
We calculate terms in parentheses: -(2(2a+3)), so:We add all the numbers together, and all the variables
2(2a+3)
We multiply parentheses
4a+6
Back to the equation:
-(4a+6)
4a-(4a+6)+26=0
We get rid of parentheses
4a-4a-6+26=0
We add all the numbers together, and all the variables
20!=0
There is no solution for this equation
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