4(a+3)=18-23(3-2a)

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Solution for 4(a+3)=18-23(3-2a) equation: 



4(a+3)=18-23(3-2a)

We move all terms to the left:

4(a+3)-(18-23(3-2a))=0

We add all the numbers together, and all the variables

4(a+3)-(18-23(-2a+3))=0

We multiply parentheses

4a-(18-23(-2a+3))+12=0



We calculate terms in parentheses: -(18-23(-2a+3)), so:

18-23(-2a+3)

determiningTheFunctionDomain
-23(-2a+3)+18

We multiply parentheses

46a-69+18

We add all the numbers together, and all the variables

46a-51

Back to the equation:

-(46a-51)



We get rid of parentheses

4a-46a+51+12=0

We add all the numbers together, and all the variables

-42a+63=0

We move all terms containing a to the left, all other terms to the right

-42a=-63

a=-63/-42

a=1+1/2

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