4(a+3)+10a=14a+12

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Solution for 4(a+3)+10a=14a+12 equation:



4(a+3)+10a=14a+12
We move all terms to the left:
4(a+3)+10a-(14a+12)=0
We add all the numbers together, and all the variables
10a+4(a+3)-(14a+12)=0
We multiply parentheses
10a+4a-(14a+12)+12=0
We get rid of parentheses
10a+4a-14a-12+12=0
We add all the numbers together, and all the variables
=0
a=0/1
a=0

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