4(a+2)+8a-4=28

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Solution for 4(a+2)+8a-4=28 equation: 



4(a+2)+8a-4=28

We move all terms to the left:

4(a+2)+8a-4-(28)=0

We add all the numbers together, and all the variables

8a+4(a+2)-32=0

We multiply parentheses

8a+4a+8-32=0

We add all the numbers together, and all the variables

12a-24=0

We move all terms containing a to the left, all other terms to the right

12a=24

a=24/12

a=2

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