4(X-10)=2x+28

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Solution for 4(X-10)=2x+28 equation: 



4(X-10)=2X+28

We move all terms to the left:

4(X-10)-(2X+28)=0

We multiply parentheses

4X-(2X+28)-40=0

We get rid of parentheses

4X-2X-28-40=0

We add all the numbers together, and all the variables

2X-68=0

We move all terms containing X to the left, all other terms to the right

2X=68

X=68/2

X=34

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