4(9c-6)=(8c-26)

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Solution for 4(9c-6)=(8c-26) equation: 



4(9c-6)=(8c-26)

We move all terms to the left:

4(9c-6)-((8c-26))=0

We multiply parentheses

36c-((8c-26))-24=0



We calculate terms in parentheses: -((8c-26)), so:

(8c-26)

We get rid of parentheses

8c-26

Back to the equation:

-(8c-26)



We get rid of parentheses

36c-8c+26-24=0

We add all the numbers together, and all the variables

28c+2=0

We move all terms containing c to the left, all other terms to the right

28c=-2

c=-2/28

c=-1/14

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