4(9-z)-48=20z-6(2+4z)

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Solution for 4(9-z)-48=20z-6(2+4z) equation: 



4(9-z)-48=20z-6(2+4z)

We move all terms to the left:

4(9-z)-48-(20z-6(2+4z))=0

We add all the numbers together, and all the variables

4(-1z+9)-(20z-6(4z+2))-48=0

We multiply parentheses

-4z-(20z-6(4z+2))+36-48=0



We calculate terms in parentheses: -(20z-6(4z+2)), so:

20z-6(4z+2)

We multiply parentheses

20z-24z-12

We add all the numbers together, and all the variables

-4z-12

Back to the equation:

-(-4z-12)



We add all the numbers together, and all the variables

-4z-(-4z-12)-12=0

We get rid of parentheses

-4z+4z+12-12=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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