4(8x+3)=40+4x

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Solution for 4(8x+3)=40+4x equation: 



4(8x+3)=40+4x

We move all terms to the left:

4(8x+3)-(40+4x)=0

We add all the numbers together, and all the variables

4(8x+3)-(4x+40)=0

We multiply parentheses

32x-(4x+40)+12=0

We get rid of parentheses

32x-4x-40+12=0

We add all the numbers together, and all the variables

28x-28=0

We move all terms containing x to the left, all other terms to the right

28x=28

x=28/28

x=1

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