4(8v+2)=28v+4v+8

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Solution for 4(8v+2)=28v+4v+8 equation: 



4(8v+2)=28v+4v+8

We move all terms to the left:

4(8v+2)-(28v+4v+8)=0

We add all the numbers together, and all the variables

4(8v+2)-(32v+8)=0

We multiply parentheses

32v-(32v+8)+8=0

We get rid of parentheses

32v-32v-8+8=0

We add all the numbers together, and all the variables

=0

v=0/1

v=0

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