4(8t+1)-8=t-(t+3)

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Solution for 4(8t+1)-8=t-(t+3) equation: 



4(8t+1)-8=t-(t+3)

We move all terms to the left:

4(8t+1)-8-(t-(t+3))=0

We multiply parentheses

32t-(t-(t+3))+4-8=0



We calculate terms in parentheses: -(t-(t+3)), so:

t-(t+3)

We get rid of parentheses

t-t-3

We add all the numbers together, and all the variables

-3

Back to the equation:

-(-3)



We add all the numbers together, and all the variables

32t-1=0

We move all terms containing t to the left, all other terms to the right

32t=1

t=1/32

t=1/32

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