4(7z-1)=23z+5z+2-6

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Solution for 4(7z-1)=23z+5z+2-6 equation: 



4(7z-1)=23z+5z+2-6

We move all terms to the left:

4(7z-1)-(23z+5z+2-6)=0

We add all the numbers together, and all the variables

4(7z-1)-(28z-4)=0

We multiply parentheses

28z-(28z-4)-4=0

We get rid of parentheses

28z-28z+4-4=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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