4(7c+1)-28=24c+4

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Solution for 4(7c+1)-28=24c+4 equation: 



4(7c+1)-28=24c+4

We move all terms to the left:

4(7c+1)-28-(24c+4)=0

We multiply parentheses

28c-(24c+4)+4-28=0

We get rid of parentheses

28c-24c-4+4-28=0

We add all the numbers together, and all the variables

4c-28=0

We move all terms containing c to the left, all other terms to the right

4c=28

c=28/4

c=7

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