4(7-k)=2(3k-11)

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Solution for 4(7-k)=2(3k-11) equation:



4(7-k)=2(3k-11)
We move all terms to the left:
4(7-k)-(2(3k-11))=0
We add all the numbers together, and all the variables
4(-1k+7)-(2(3k-11))=0
We multiply parentheses
-4k-(2(3k-11))+28=0
We calculate terms in parentheses: -(2(3k-11)), so:
2(3k-11)
We multiply parentheses
6k-22
Back to the equation:
-(6k-22)
We get rid of parentheses
-4k-6k+22+28=0
We add all the numbers together, and all the variables
-10k+50=0
We move all terms containing k to the left, all other terms to the right
-10k=-50
k=-50/-10
k=+5

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