4(7-2x)=3(x+4)

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Solution for 4(7-2x)=3(x+4) equation: 



4(7-2x)=3(x+4)

We move all terms to the left:

4(7-2x)-(3(x+4))=0

We add all the numbers together, and all the variables

4(-2x+7)-(3(x+4))=0

We multiply parentheses

-8x-(3(x+4))+28=0



We calculate terms in parentheses: -(3(x+4)), so:

3(x+4)

We multiply parentheses

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

-8x-3x-12+28=0

We add all the numbers together, and all the variables

-11x+16=0

We move all terms containing x to the left, all other terms to the right

-11x=-16

x=-16/-11

x=1+5/11

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