4(6z-1)-2(z+4)=19(z+1)

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Solution for 4(6z-1)-2(z+4)=19(z+1) equation: 



4(6z-1)-2(z+4)=19(z+1)

We move all terms to the left:

4(6z-1)-2(z+4)-(19(z+1))=0

We multiply parentheses

24z-2z-(19(z+1))-4-8=0



We calculate terms in parentheses: -(19(z+1)), so:

19(z+1)

We multiply parentheses

19z+19

Back to the equation:

-(19z+19)



We add all the numbers together, and all the variables

22z-(19z+19)-12=0

We get rid of parentheses

22z-19z-19-12=0

We add all the numbers together, and all the variables

3z-31=0

We move all terms containing z to the left, all other terms to the right

3z=31

z=31/3

z=10+1/3

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