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4(6x-1)x=5(5x-1)
We move all terms to the left:
4(6x-1)x-(5(5x-1))=0
We multiply parentheses
24x^2-4x-(5(5x-1))=0
We calculate terms in parentheses: -(5(5x-1)), so:We get rid of parentheses
5(5x-1)
We multiply parentheses
25x-5
Back to the equation:
-(25x-5)
24x^2-4x-25x+5=0
We add all the numbers together, and all the variables
24x^2-29x+5=0
a = 24; b = -29; c = +5;
Δ = b2-4ac
Δ = -292-4·24·5
Δ = 361
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{361}=19$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-19}{2*24}=\frac{10}{48} =5/24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+19}{2*24}=\frac{48}{48} =1 $
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