4(6q-3)=3(2q+2)

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Solution for 4(6q-3)=3(2q+2) equation:



4(6q-3)=3(2q+2)
We move all terms to the left:
4(6q-3)-(3(2q+2))=0
We multiply parentheses
24q-(3(2q+2))-12=0
We calculate terms in parentheses: -(3(2q+2)), so:
3(2q+2)
We multiply parentheses
6q+6
Back to the equation:
-(6q+6)
We get rid of parentheses
24q-6q-6-12=0
We add all the numbers together, and all the variables
18q-18=0
We move all terms containing q to the left, all other terms to the right
18q=18
q=18/18
q=1

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