4(6j-15)=6(38-3j)

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Solution for 4(6j-15)=6(38-3j) equation: 



4(6j-15)=6(38-3j)

We move all terms to the left:

4(6j-15)-(6(38-3j))=0

We add all the numbers together, and all the variables

4(6j-15)-(6(-3j+38))=0

We multiply parentheses

24j-(6(-3j+38))-60=0



We calculate terms in parentheses: -(6(-3j+38)), so:

6(-3j+38)

We multiply parentheses

-18j+228

Back to the equation:

-(-18j+228)



We get rid of parentheses

24j+18j-228-60=0

We add all the numbers together, and all the variables

42j-288=0

We move all terms containing j to the left, all other terms to the right

42j=288

j=288/42

j=6+6/7

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