4(6c-5)+5=3(4c-1)

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Solution for 4(6c-5)+5=3(4c-1) equation: 



4(6c-5)+5=3(4c-1)

We move all terms to the left:

4(6c-5)+5-(3(4c-1))=0

We multiply parentheses

24c-(3(4c-1))-20+5=0



We calculate terms in parentheses: -(3(4c-1)), so:

3(4c-1)

We multiply parentheses

12c-3

Back to the equation:

-(12c-3)



We add all the numbers together, and all the variables

24c-(12c-3)-15=0

We get rid of parentheses

24c-12c+3-15=0

We add all the numbers together, and all the variables

12c-12=0

We move all terms containing c to the left, all other terms to the right

12c=12

c=12/12

c=1

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