4(6b-7)+6(b+2)=44

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Solution for 4(6b-7)+6(b+2)=44 equation: 



4(6b-7)+6(b+2)=44

We move all terms to the left:

4(6b-7)+6(b+2)-(44)=0

We multiply parentheses

24b+6b-28+12-44=0

We add all the numbers together, and all the variables

30b-60=0

We move all terms containing b to the left, all other terms to the right

30b=60

b=60/30

b=2

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