4(6-x)-5(x+3)-8=6(x-2)+3

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Solution for 4(6-x)-5(x+3)-8=6(x-2)+3 equation: 



4(6-x)-5(x+3)-8=6(x-2)+3

We move all terms to the left:

4(6-x)-5(x+3)-8-(6(x-2)+3)=0

We add all the numbers together, and all the variables

4(-1x+6)-5(x+3)-(6(x-2)+3)-8=0

We multiply parentheses

-4x-5x-(6(x-2)+3)+24-15-8=0



We calculate terms in parentheses: -(6(x-2)+3), so:

6(x-2)+3

We multiply parentheses

6x-12+3

We add all the numbers together, and all the variables

6x-9

Back to the equation:

-(6x-9)



We add all the numbers together, and all the variables

-9x-(6x-9)+1=0

We get rid of parentheses

-9x-6x+9+1=0

We add all the numbers together, and all the variables

-15x+10=0

We move all terms containing x to the left, all other terms to the right

-15x=-10

x=-10/-15

x=2/3

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