4(6-3z)=72

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Solution for 4(6-3z)=72 equation: 



4(6-3z)=72

We move all terms to the left:

4(6-3z)-(72)=0

We add all the numbers together, and all the variables

4(-3z+6)-72=0

We multiply parentheses

-12z+24-72=0

We add all the numbers together, and all the variables

-12z-48=0

We move all terms containing z to the left, all other terms to the right

-12z=48

z=48/-12

z=-4

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