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4(6-3x)=22-3(5x+19)
We move all terms to the left:
4(6-3x)-(22-3(5x+19))=0
We add all the numbers together, and all the variables
4(-3x+6)-(22-3(5x+19))=0
We multiply parentheses
-12x-(22-3(5x+19))+24=0
We calculate terms in parentheses: -(22-3(5x+19)), so:We get rid of parentheses
22-3(5x+19)
determiningTheFunctionDomain -3(5x+19)+22
We multiply parentheses
-15x-57+22
We add all the numbers together, and all the variables
-15x-35
Back to the equation:
-(-15x-35)
-12x+15x+35+24=0
We add all the numbers together, and all the variables
3x+59=0
We move all terms containing x to the left, all other terms to the right
3x=-59
x=-59/3
x=-19+2/3
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