4(6-2z)-3z=6z-129

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Solution for 4(6-2z)-3z=6z-129 equation: 



4(6-2z)-3z=6z-129

We move all terms to the left:

4(6-2z)-3z-(6z-129)=0

We add all the numbers together, and all the variables

4(-2z+6)-3z-(6z-129)=0

We add all the numbers together, and all the variables

-3z+4(-2z+6)-(6z-129)=0

We multiply parentheses

-3z-8z-(6z-129)+24=0

We get rid of parentheses

-3z-8z-6z+129+24=0

We add all the numbers together, and all the variables

-17z+153=0

We move all terms containing z to the left, all other terms to the right

-17z=-153

z=-153/-17

z=+9

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