4(6+v)=4(-4+2v)

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Solution for 4(6+v)=4(-4+2v) equation: 



4(6+v)=4(-4+2v)

We move all terms to the left:

4(6+v)-(4(-4+2v))=0

We add all the numbers together, and all the variables

4(v+6)-(4(2v-4))=0

We multiply parentheses

4v-(4(2v-4))+24=0



We calculate terms in parentheses: -(4(2v-4)), so:

4(2v-4)

We multiply parentheses

8v-16

Back to the equation:

-(8v-16)



We get rid of parentheses

4v-8v+16+24=0

We add all the numbers together, and all the variables

-4v+40=0

We move all terms containing v to the left, all other terms to the right

-4v=-40

v=-40/-4

v=+10

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