4(5z+1)=-(15z+11)

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Solution for 4(5z+1)=-(15z+11) equation: 



4(5z+1)=-(15z+11)

We move all terms to the left:

4(5z+1)-(-(15z+11))=0

We multiply parentheses

20z-(-(15z+11))+4=0



We calculate terms in parentheses: -(-(15z+11)), so:

-(15z+11)

We get rid of parentheses

-15z-11

Back to the equation:

-(-15z-11)



We get rid of parentheses

20z+15z+11+4=0

We add all the numbers together, and all the variables

35z+15=0

We move all terms containing z to the left, all other terms to the right

35z=-15

z=-15/35

z=-3/7

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