4(5y-4(y-1))=3(4(y+1))

Solution for 4(5y-4(y-1))=3(4(y+1)) equation:

Simplifying
4(5y + -4(y + -1)) = 3(4(y + 1))

Reorder the terms:
4(5y + -4(-1 + y)) = 3(4(y + 1))
4(5y + (-1 * -4 + y * -4)) = 3(4(y + 1))
4(5y + (4 + -4y)) = 3(4(y + 1))

Reorder the terms:
4(4 + 5y + -4y) = 3(4(y + 1))

Combine like terms: 5y + -4y = 1y
4(4 + 1y) = 3(4(y + 1))
(4 * 4 + 1y * 4) = 3(4(y + 1))
(16 + 4y) = 3(4(y + 1))

Reorder the terms:
16 + 4y = 3(4(1 + y))
16 + 4y = 3((1 * 4 + y * 4))
16 + 4y = 3((4 + 4y))
16 + 4y = (4 * 3 + 4y * 3)
16 + 4y = (12 + 12y)

Solving
16 + 4y = 12 + 12y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-12y' to each side of the equation.
16 + 4y + -12y = 12 + 12y + -12y

Combine like terms: 4y + -12y = -8y
16 + -8y = 12 + 12y + -12y

Combine like terms: 12y + -12y = 0
16 + -8y = 12 + 0
16 + -8y = 12

Add '-16' to each side of the equation.
16 + -16 + -8y = 12 + -16

Combine like terms: 16 + -16 = 0
0 + -8y = 12 + -16
-8y = 12 + -16

Combine like terms: 12 + -16 = -4
-8y = -4

Divide each side by '-8'.
y = 0.5

Simplifying
y = 0.5