4(5y+3)-5(3y+1)=27

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Solution for 4(5y+3)-5(3y+1)=27 equation:


Simplifying
4(5y + 3) + -5(3y + 1) = 27

Reorder the terms:
4(3 + 5y) + -5(3y + 1) = 27
(3 * 4 + 5y * 4) + -5(3y + 1) = 27
(12 + 20y) + -5(3y + 1) = 27

Reorder the terms:
12 + 20y + -5(1 + 3y) = 27
12 + 20y + (1 * -5 + 3y * -5) = 27
12 + 20y + (-5 + -15y) = 27

Reorder the terms:
12 + -5 + 20y + -15y = 27

Combine like terms: 12 + -5 = 7
7 + 20y + -15y = 27

Combine like terms: 20y + -15y = 5y
7 + 5y = 27

Solving
7 + 5y = 27

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 5y = 27 + -7

Combine like terms: 7 + -7 = 0
0 + 5y = 27 + -7
5y = 27 + -7

Combine like terms: 27 + -7 = 20
5y = 20

Divide each side by '5'.
y = 4

Simplifying
y = 4

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