4(5x2-4)=4x2

Solution for 4(5x2-4)=4x2 equation:

4(5x^2-4)=4x^2

We move all terms to the left:

4(5x^2-4)-(4x^2)=0

determiningTheFunctionDomain
-4x^2+4(5x^2-4)=0

We multiply parentheses

-4x^2+20x^2-16=0

We add all the numbers together, and all the variables

16x^2-16=0

a = 16; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·16·(-16)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-32}{2*16}=\frac{-32}{32}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+32}{2*16}=\frac{32}{32}
=1
$