4(5x-7)-21=13(x-2)

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Solution for 4(5x-7)-21=13(x-2) equation: 



4(5x-7)-21=13(x-2)

We move all terms to the left:

4(5x-7)-21-(13(x-2))=0

We multiply parentheses

20x-(13(x-2))-28-21=0



We calculate terms in parentheses: -(13(x-2)), so:

13(x-2)

We multiply parentheses

13x-26

Back to the equation:

-(13x-26)



We add all the numbers together, and all the variables

20x-(13x-26)-49=0

We get rid of parentheses

20x-13x+26-49=0

We add all the numbers together, and all the variables

7x-23=0

We move all terms containing x to the left, all other terms to the right

7x=23

x=23/7

x=3+2/7

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