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4(5x-5)+3(15-3x)-5(2x+3=1
We move all terms to the left:
4(5x-5)+3(15-3x)-5(2x+3-(1)=0
We add all the numbers together, and all the variables
4(5x-5)+3(-3x+15)-5(2x+3-1=0
We multiply parentheses
20x-9x-5(2x+3-1-20+45=0
We add all the numbers together, and all the variables
11x-5(2x+3-1-20+45=0
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