4(5x-5)+1=7-3(4-2x)

Solution for 4(5x-5)+1=7-3(4-2x) equation:

4(5x-5)+1=7-3(4-2x)

We move all terms to the left:

4(5x-5)+1-(7-3(4-2x))=0

We add all the numbers together, and all the variables

4(5x-5)-(7-3(-2x+4))+1=0

We multiply parentheses

20x-(7-3(-2x+4))-20+1=0


We calculate terms in parentheses: -(7-3(-2x+4)), so:

7-3(-2x+4)

determiningTheFunctionDomain
-3(-2x+4)+7

We multiply parentheses

6x-12+7

We add all the numbers together, and all the variables

6x-5

Back to the equation:

-(6x-5)


We add all the numbers together, and all the variables

20x-(6x-5)-19=0

We get rid of parentheses

20x-6x+5-19=0

We add all the numbers together, and all the variables

14x-14=0

We move all terms containing x to the left, all other terms to the right

14x=14

x=14/14

x=1