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4(5x-2)-6x=3(3x+2)+1
We move all terms to the left:
4(5x-2)-6x-(3(3x+2)+1)=0
We add all the numbers together, and all the variables
-6x+4(5x-2)-(3(3x+2)+1)=0
We multiply parentheses
-6x+20x-(3(3x+2)+1)-8=0
We calculate terms in parentheses: -(3(3x+2)+1), so:We add all the numbers together, and all the variables
3(3x+2)+1
We multiply parentheses
9x+6+1
We add all the numbers together, and all the variables
9x+7
Back to the equation:
-(9x+7)
14x-(9x+7)-8=0
We get rid of parentheses
14x-9x-7-8=0
We add all the numbers together, and all the variables
5x-15=0
We move all terms containing x to the left, all other terms to the right
5x=15
x=15/5
x=3
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